I need to write a program that creates a 2d array in variable "numbers" in rows (5) and columns (4). The elements of the array have to be consecutive integers starting at 1 and end at 20. I have to use "for" loop.
[ 1, 2, 3, 4 ],
[ 5, 6, 7, 8 ],
[ 9, 10, 11, 12 ],
[ 13, 14, 15, 16 ],
[ 17, 18, 19, 20 ],
So I came up with that:
const numbers = [];
const columns = 4;
const rows = 5;
for (let i = 0; i < rows; i++) {
numbers [i] = [];
for (let j = 0; j < columns; j++){
numbers [i][j] = j + 1;
}
}
console.log(numbers);
But the result of this is five identical rows, like this:
[ 1, 2, 3, 4 ],
[ 1, 2, 3, 4 ],
[ 1, 2, 3, 4 ],
[ 1, 2, 3, 4 ],
[ 1, 2, 3, 4 ]
Do you have any idea how to fix it? How to make second row starting from 5?
Looks like in the second loop, you should do numbers [i][j] = j * i; instead
Every time the outer for loop starts a new iteration, j is reset back to 0, which is why you keep getting rows starting with 1.
To fix this, you could declare a variable outside of the for loops that tracks the current number, and use that instead of j like so:
const numbers = [];
const columns = 4;
const rows = 5;
let currNum = 0;
for (let i = 0; i < rows; i++) {
numbers [i] = [];
for (let j = 0; j < columns; j++){
currNum++;
numbers [i][j] = currNum;
}
}
console.log(numbers);
Here is some updated code. You need to add i*columns to every value
const numbers = [];
const columns = 4;
const rows = 5;
for (let i = 0; i < rows; i++) {
numbers[i] = [];
for (let j = 0; j < columns; j++){
numbers[i][j] = j + 1 + (i*columns);
}
}
console.log(numbers);